(X+5)/(4x^2+23x+18)

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Solution for (X+5)/(4x^2+23x+18) equation: 


D( x )

4*x^2+23*x+18 = 0

4*x^2+23*x+18 = 0

4*x^2+23*x+18 = 0

4*x^2+23*x+18 = 0

DELTA = 23^2-(4*4*18)

DELTA = 241

DELTA > 0

x = (241^(1/2)-23)/(2*4) or x = (-241^(1/2)-23)/(2*4)

x = (241^(1/2)-23)/8 or x = (-(241^(1/2)+23))/8

x in (-oo:(-(241^(1/2)+23))/8) U ((-(241^(1/2)+23))/8:(241^(1/2)-23)/8) U ((241^(1/2)-23)/8:+oo)

(X+5)/(4*x^2+23*x+18) = 0

4*x^2+23*x+18 = 0

4*x^2+23*x+18 = 0

DELTA = 23^2-(4*4*18)

DELTA = 241

DELTA > 0

x = (241^(1/2)-23)/(2*4) or x = (-241^(1/2)-23)/(2*4)

x = (241^(1/2)-23)/8 or x = (-(241^(1/2)+23))/8

(x+(241^(1/2)+23)/8)*(x-((241^(1/2)-23)/8)) = 0

(X+5)/((x+(241^(1/2)+23)/8)*(x-((241^(1/2)-23)/8))) = 0

x belongs to the empty set

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